Question

a bucket contains 15 blue pens 35 black pins and 40 Red Pins. You pick one pin at random find the theoretical probabilities below . Express your answer as a percent to the nearest whole number p(black)=???p(blue or black)=???

Answer 1

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Answer 2

The number of blue pen is 15

The number of black pens is 35

The number of red pens is 40

The total number of pens in the bucket = Blue pens + black pens + red pens

The total number of pens = 15 + 35 + 40

= 90

Therefore, the total number of pens in the bucket = 90 pens

The probability that black pen is picked is

Probablity = possible outcomes/ total outcomes

P(black) = 35 / 90 x 100%

P(black) = 0.3888 x 100%

P(black) = 38.88%

P(black) = 39%

P(blue or black)

If its pick at random without replacement then

If the first pick is blue, then the total number of pen in the bucket remains 89

For the first pick will be 15/90

Since the remaining pens is 89, then the second pick is

35/89

Then we have

15/90 + 35/89

LCM is 8010

8010 x 15 / 90 + 35 x 8010 /89 / 8010

89 x 15 + 35 x 90 / 8010

P(blue / black) = 1335 + 3150 / 8010

P(blue or black) = 4485 / 8010

P(blue or black) = 0.559 x 100%

P(blue or black) = 55.9%

P(blue or black) = 56%