Answer:
d . 6 times the secondary turns in the second type of transformer
Step-by-step explanation:
In transformer , voltage is increased or decreased according to ratio of no of turns in secondary to no of turns in primary coil . The relation is as follows
V₂ / V₁ = n₂/n₁
n₁ and n₂ are no of turns in primary and secondary coil and V₁ and V₂ are voltage in primary and secondary coil.
for first type , Let no of turn in primary = n and no of turn in secondary = n₁
V₂ / V₁ = 3
so
n₁/n = 3
n = n₁ /3
n₁ = 3n
For second type , let no of turn in secondary = n₂
V₂ / V₁ = .5
n₂/n = .5
n₂ = .5n
n₂ / n₁ = .5n / 3n
n₂ / n₁ = 1 / 6
n₁ = 6n₂
option d is correct .