Question

2. Write ONE algebraic rule that represents triangle JKL being translated to triangle J"K"L".

Answer 1

The original coordinates of JKL:

J(-3, -3), K(-4, 2) and L(2,1)

First, it is translated by the algebraic rule (x,y)->(x+2, y-3):

J(-3, -3)-> J'(-3+2, -3-3)=J'(-1, -6)

K(-4, 2) -> K'(-4+2, 2-3)= K'(-2, -1)

L(2,1) -> L'(2+2, 1-3)= L'(4, -2)

Then, this image is translated by (x,y)-> (x-2, y-1)

J'(-1, -6) -> J''(-1-2, -6-1) = J''(-3, -7)

K'(-2, -1) -> K''(-2-2, -1-1)= K''(-4, -2)

L'(4, -2) -> L''(4-2, -2-1)= L''( 2, -3)

Coordinates for triangle J''K''L'':

J''(-3, -7), K''(-4, -2) and L''( 2, -3)

2. To find algebraic rule that represents JKL to J''K''L'':

`\begin{gathered} J^(\doubleprime)(-3,-7)\text{ and J(-3, -3)} \\ (x,y)\rightarrow(x,\text{ y+4)} \end{gathered}`