525,516 views
2 votes
2 votes
Change the function, y=3(0.5)^x,to a function with base e

User Vaizki
by
2.9k points

2 Answers

23 votes
23 votes

Answer:

y=3e^(ln0.5)x

Step-by-step explanation:

User Vinnief
by
3.0k points
18 votes
18 votes

Answer:

y = 3(e)^(-0.69x)

Step-by-step explanation:

Taking into account the following property


a=e^(\ln a)

We can replace (0.5)^x by


\begin{gathered} 0.5^x=e^{\ln \text{ (0.5\textasciicircum{}x)}} \\ 0.5^x=e^(x\ln (0.5)) \end{gathered}

So, now we can rewrite the function as


\begin{gathered} y=3e^(x\ln (0.5)) \\ y=3e^(x(-0.69)) \\ y=3e^(-0.69x) \end{gathered}

Therefore, the answer is

y = 3(e)^(-0.69x)

User Vakindu
by
2.8k points
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