Question

What is the number and type of roots for the equation 7x^2+8x-12=2x^2+14x-4?

Answer 1

7x^2+8x-12=2x^2+14x-4

⇒ 7x^2 - 2x^2 + 8x - 14x -12 +4 = 0

⇒ 5x^2 - 6x - 8 = 0

b^2 - 4ac = (-6)^2 - 4 * 5 * (-8) = 36 + 160 = 196 > 0

So there are two real roots.

Hope it helps!

Answer 2

I hope this helps you



7x^2+8x-12-2x^2-14x+4=0


5x^2-6x-8=0



a=5 b= -6 c= -8



disctirminant =b^2-4ac



disctirminant =(-6)^2-4.5. (-8)



disctirminant =36+160



disctirminant =196


x1=6+ square root of 196/2.5



x1=3+2 square root of 3/5


x2=3- square root of 3/5