Question

The student Advisory Council here at PC sells red and pink carnations every year for Valentine’s Day. The number of red carnations sold was 1 less than 3 times the number of pink carnations sold. Red carnations were sold for $0.60 each and Pink Carnations sold for $0.80 each. The club made $600.00. How many of each carnation were sold?

Please help!!

Answer 1

The number of :

Red carnations sold = x = 692 carnations

Pink carnations sold = y = 231 carnations

Explanation:

Let us represent

The number of :

Red carnations = x

Pink carnations = y

The Student Advisory Council here at PC sells red and pink carnations every year for Valentine's Day.

The number of red carnations sold was 1 less than 3 times the number of pink carnations sold.

x = 3y - 1 .....Equation 1

Red carnations were sold for $0.60 each and Pink Carnations sold for $0.80 each. The club made $600.00. .

$0.60 × x + 0.80 × y = $600

0.6x + 0.80y = 600...... Equation 2

Using substitution method:

Let us substitute, 3y - 1 for x in Equation 2

0.6(3y - 1) + 0.80y = 600

1.8y - 0.6 + 0.80y = 600

1.8y + 0.80y = 600 + 0.6

2.6y = 600.6

y = 600.6 ÷ 2.6

y = 231 carnations

Solving for x

x = 3y - 1 .....Equation 1

x = 3(231) - 1

x =693 − 1

x = 692 carnations

Therefore, The number of :

Red carnations = x = 692 carnations

Pink carnations = y = 231 carnations