Question

What is the position vector of the midpoint of the line PQ if P has coordinates(-13,-4,6) and Q has coordinates (0,4,11)?OA. ( 130 - 17)B.(-13,0,1)c. (2.0.1D. (-2,0. - 1)

Answer 1

The general formula to find the midpoint of a line in a 3D space is given by

`M=((x_1+x_2)/(2),(y_1+y_2)/(2),(z_1+z_2)/(2))`

In this case, we have

`M=((-13+0)/(2),(-4+4)/(2),(6+11)/(2))=((-13)/(2),0,(17)/(2))`

So the position vector of the midpoint of the line PQ is

`M=(-(13)/(2),0,(17)/(2))`

which is option B.