Question

(HELP ME PLS, 10TH GRADE GEOMETRY) Two parallel lines are crossed by a transversal.

If m1 = 61.8°, then m6 is ... ?

A.61.8

B.81.8

C.98.2

D.118.2

Answer 1

m<8 = m<1 = 61.8°

m<6 = 180 - m<8
m<6 = 180 - 61.8
m<6 = 118.2

answer: D.118.2

Answer 2

we know that

m∠1+m∠2=
`180\°` -------> by supplementary angles

we have

m∠1=
`61.8\°`

substitute

m∠2=
`180\°-61.8\°=118.2\°`

m∠6=m∠2 -------> by corresponding angles

so

m∠6=
`118.2\°`

therefore

the answer is the option D

`118.2\°`