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What is the vertex form of f(x)=2x^2 + 6x-8

What is the vertex form of f(x)=2x^2 + 6x-8
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What is the vertex form of f(x)=2x^2 + 6x-8

User Nbering
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2 Answers

7 votes
In vertex form, the answer would be (-3/2, -25/2)


User Spikeheap
by
8.5k points
3 votes
-b/a

-6/2

x=-3

y=2(-3)^2+6(-3)-8 = 18-18-8 = -8

(-3, -8)
User LolaRun
by
8.1k points
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