Question

If 2/5 ton of concrete covers 5/6 of a wall, how much concrete is required to cover the entire wall

Answer 1

Note¹: One integer is 6/6 of the wall
Note²: Make the rule of three simple

ton __ Coverage

`(2)/(5)` ---------------
`(5)/(6)`
y ---------------
`(6)/(6)`

Solving: (directly proportional)


`( (2)/(5) )/(y)= ( (5)/(6) )/( (6)/(6) )`

Product of extremes equals product of means


`(5)/(6) *y = (2)/(5) * (6)/(6)`


`(5y)/(6) = (12)/(30)`

Product of extremes equals product of means


`5y*30 = 6*12`

`150y = 72`

`y = (72)/(150) (/6)/(/6) \to \boxed{\boxed{y = (12)/(25) }}\end{array}}\qquad\quad\checkmark`

Answer:

`(12)/(25)\:\textbf{ton\:of\:concrete}` or 0.48 ton of concrete