Question

Two people compete in a five-mile go kart race. Person A travels 1/10 miles every 15 seconds while Person B travels 3/8 mile every 48 seconds. Who wins the race? What is the difference of the finish times of the competitors?

Answer 1

a) Person B wins the race.

b) The difference in the finish times of the competitors is 110 s.

Explanation:

a) We can find the time that takes Person A and B to finish the race:

Person A:

`t_{F_(A)} = (t_(A))/(d_(A))*d_(T)`

Where:

`t_(A)`: is the time of Person A = 15 s [/tex]

`d_(A)`: is the distance of Person A = 1/10 miles [/tex]

`d_(T)`: is the total distance = 5 miles [/tex]

`t_{F_(A)} = (15 s)/(1/10 miles)*5 miles = 750 s`

Person B:

`t_{F_(B)} = (t_(B))/(d_(B))*d_(T) = (48 s)/(3/8 miles)*5 miles = 640 s`

Hence, Person B wins the race.

b) The difference in the finish times is:

`t_{F_(A)} - t_{F_(B)} = 750 s - 640 s = 110 s`

Therefore, the difference in the finish times of the competitors is 110 s.

I hope it helps you!