Question

The equation of a parabola is x^2=8y
what is the value of a for the given parabola

Answer 1

`\bf \textit{vertex form of a parabola}\\\\ \boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\ x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -----------------------------\\\\ x^2=8y\implies (x-0)^2=8y\implies \cfrac{(x-0)^2}{8}=(y-0) \\\\\\ \cfrac{1}{8}(x-0)^2=(y-0)\implies \boxed{\cfrac{1}{8}(x-0)^2+0=y}`