Question

Ten grams of a gas occupies 12.5 liters at a pressure of 42.0 cm Hg. What is the volume when the pressure has increased to 75.0 cm Hg? 6.00 L 7.00 L 8.00 L none of the above

Answer 1

Using boyles law
12.5×42=75×v
So.v=7l

Answer 2

7.0 L

Solution:

According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportinal to the applied Pressure". Mathematically, the initial and final states of gas are given as,

P₁ V₁ = P₂ V₂ ----------- (1)

Data Given;

P₁ = 42.0 cm Hg

V₁ = 12.5 L

P₂ = 75.0 cm Hg

V₂ = ??

Solving equation 1 for V₂,

V₂ = P₁ V₁ / P₂

Putting values,

V₂ = (42.0 cm Hg × 12.5 L) ÷ 75.0 cm Hg

V₂ = 7.0 L

Result:

As the Pressure has increased from 42.0 cm Hg to 75.0 cm Hg, therefore, Volume got decreased from 12.5 L to 7.0 L.