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Two of the desserts are sugar/free. Three of the drinks are sugar-free. A meal deal combination is selected at random. Work out the probability that both the desserts and the drink are sugar free. Give your answer as a fraction

User Idalis
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Final answer:

To find the probability that both the desserts and the drink are sugar-free, we divide the number of favorable outcomes (those where both the dessert and drink are sugar-free) by the total number of possible outcomes.

Step-by-step explanation:

To find the probability that both the desserts and the drink are sugar-free, we need to consider the number of sugar-free options for each category. We are given that two desserts are sugar-free and three drinks are sugar-free. To find the probability, we divide the number of favorable outcomes (those where both the dessert and drink are sugar-free) by the total number of possible outcomes (all the meal deal combinations).

The total number of possible outcomes is the product of the number of dessert options and the number of drink options. In this case, the number of dessert options is 2 and the number of drink options is 3, so the total number of possible outcomes is 2 * 3 = 6.

Now, the number of favorable outcomes is the number of combinations where both the dessert and drink are sugar-free. Since there are 2 sugar-free desserts and 3 sugar-free drinks, the number of favorable outcomes is 2 * 3 = 6.

Finally, we divide the number of favorable outcomes by the total number of possible outcomes to find the probability:

Probability = Number of favorable outcomes / Total number of possible outcomes = 6 / 6 = 1.

Therefore, the probability that both the desserts and the drink are sugar-free is 1, which can also be written as the fraction 1/1.

User Phil Weaver
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