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What is the energy in electron-volts (eV) of a photon of green light that has a wavelength of 520 nm? (1.0 m = 1.0 × 10^-9m)

3.8 × 10^-19eV
3.4 × 10^-40eV
2.4eV
2.2 × 10^-21eV

User Fydo
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5.7k points

1 Answer

1 vote

Answer:

The energy of a photon is
3.8*10^(-19)\ eV.

Step-by-step explanation:

Given that,

Wave length = 520 nm


1 nm = 1* 10^(-9)\ m

Using plank's equation


E =h\\u...(I)

Here, h = plank constant

υ = frequency

Now, using wave equation


c =\lambda* \\u

The equation can be written as:


\\u = (c)/(\lambda)

Here, c = speed of light

λ= wave length of light

Put the value of υ in equation (I)

The energy of photon is


E = h*(c)/(\lambda)


E = (6.63*10^(-34)*3*10^(8))/(520*10^(-9))


E=3.8*10^(-19)\ eV

Hence, The energy of a photon is
3.8*10^(-19)\ eV.

User R M
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6.0k points