Question

4. An object of mass 30 kg is being pulled ona friction less horizontal surface by means ofa string that makes an angle of 20 degree with thehorizontal. If the tension in the string is 50 Ncalculate the acceleration of the object. (1 point)A. O 1.566 m/s²B. 0.607 m/sC. O 0.57 m/s ²D. O1.667 m/sE. 09.8 m/s ²

Answer 1

A. 1.566 m/s²

Step-by-step explanation

Step 1

free body diagram

F.B.D

Step 2

Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate,it is represented in the formula

`\begin{gathered} F=m*a \\ where\text{ m is the mass} \\ a\text{ is the acceleration} \end{gathered}`

so,for the x-axis we have

`\begin{gathered} tcos\theta=ma \\ replace \\ 50*cos20=30kg*a \\ 46.98=30a \\ divide\text{ both sides by 30} \\ (46.98)/(30)=(30a)/(30) \\ 1.566(m)/(s^2)=a \end{gathered}`

therefore, the answer is

A. 1.566 m/s²

I hope this helps you