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Find two consecutive integers such that seven times the first equals six times the second
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Find two consecutive integers such that seven times the first equals six times the second

User Jmtd
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1 Answer

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Odd integers are always one more that an even integer:
1st: 2n+1
2nd: 2n+3
------------
EQUATION:
7(2n+1) = 5(2n+3)

14n+7 = 10n+15
4n = 8
n = 2
------------
1st: 2n+1 = 5
2nd: 2n+3 = 7
User Safetyduck
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