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38 votes
Can you please help me

User Mateusz
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1 Answer

8 votes
8 votes

Let:

A=(-4,10)=(x1,y1)

B=(-8,1)=(x2,y2)


m_(AB)=(1-10)/(-8-(-4))=(-9)/(-4)=(9)/(4)=2.25

C=(-5,7)=(x1',y1')

D=(-2,4)=(x2',y2')


m_(CD)=(y2^(\prime)-y1^(\prime))/(x2^(\prime)-x1^(\prime))=(4-7)/(-2-(-5))=-(3)/(3)=-1

E=(2,-3)=(x1'',y1'')

F=(6,-7)=(x2'',y2'')


m_(EF)=(y2^(\doubleprime)-y1^(\doubleprime))/(x2^(\doubleprime)-x1^(\doubleprime))=(-7-(-3))/(6-2)=(-4)/(4)=-1

Since:


\begin{gathered} m_(CD)=m_(EF) \\ -1=-1 \end{gathered}

The lines CD and EF are parallel

User Radzak
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