Question

I need a break down answer and the correct answer

Answer 1

We want the equation of the line that is parallel to the given line and passes through the given point;

`(-6,2)\text{ }y=-(2)/(3)x-3`

For the equation, the slope can be seen to be;

`m=-(2)/(3)`

The line we want to get will have this same slope and pass through the given point, so in point slope form, we have;

`\begin{gathered} y-2=-(2)/(3)(x+6) \\ y-2=-(2)/(3)x-4 \\ y=-(2)/(3)x-2 \end{gathered}`

Thus, the answer is;

`y=-(2)/(3)x-2`