Question

How many grams of HNO3 are required to prepare 500 mL of a 0.601 M HNO3 solution?

Answer 1

mass of HNO3 = ? V = 0.5L M.mass of HNO3 = 63.0067u Molarity = 0.601 molarity = no of moles of solute/volume of solution in L 0.601 = no of moles of solute/0.5 no of moles of solute = 0.3005 mass of HNO3 = no of moles * M.mass = 0.3005*63.0067 = 18.933g