Question

Z² = 0.64
solve the equation
z = ​ ± ____

Answer 1

squar root both sides
z=+/-0.8
if you are having trouble wit the decimals

0.64=64/100
so if you squar root both sides
remember
`\sqrt{ (x)/(y) } = ( √(x) )/( √(y) )` so

`\sqrt{ (64)/(100) } = ( √(64) )/( √(100) ) = ( √(8) )/( √(10) )`=+/-0.8

Answer 2

`z = \pm 0.8`

Explanation:

Use exponent rules:

`\sqrt[n]{x^n} = x`

Solve the equation:

`z^2 = 0.64`

Taking square root both sides we have;

`√(z^2) = \pm √(0.64)`

Apply the exponent rule we have;

`z = \pm √(0.64)`

We can write 0.64 as:

`0.64 = 0.8 \cdot 0.8 = (0.8)^2`

then;

`z = \pm √((0.8)^2)`

Simplify:

`z = \pm 0.8`