Answer:
In equation A, x= -1 and y= 3
In equation B, x= 12 and y= 16
Explanation:
Given the expression
(x + yi) + (4 – 7i) = 3 – 4i
We are to find the value of x and y
Expand the equation;
(x + yi) + (4 – 7i) = 3 – 4i
x + yi + 4 – 7i = 3 – 4i
x+4+yi-7i = 3 - 4i
x+4 + (y-7)i = 3-4i
Equate the real part
x+4 = 3
x = 3-4
x = -1
Equate the imaginary part;
y - 7 = -4
y = -4 + 7
y = 3
In equation A, x= -1 and y= 3
For equation B:
(x + yi) - (-6 + 14i) = 18 + 2i
x+yi+6-14i = 18+2i
x+6+(y-14)i = 18+2i
x+6 = 18
x = 18-6
x = 12
Equate the imaginary part;
y - 14 = 2
y = 2 + 14
y = 16
Hence In equation B, x=12 and y= 16