Question

Interpret the following equation for a chemical reaction using the coefficients given:H2(g) + I2(g) 2 HI(g)

Answer 1

First, we are going to interpret the reaction on the molar level:

`1\text{ mole of H}_2\text{ reacts with 1 mole of I}_2\text{ to form 2 moles of HI.}`

Now, we are going to calculate the molecular weights to do the particulate level:

`\begin{gathered} M.W.\text{ H}_2=\text{ 2 g/mol} \\ M.W.\text{ I}_2\text{ = 127*2=254 g/mol} \\ M.W.\text{ HI = 1+127= 128 g/mol} \end{gathered}`

Then, the interpretation is:

`2\text{ g of H}_2\text{ react with 254 g of I}_2\text{ to form 256 g of HI. }`