Question

A spring has a spring constant of 56 N/m. How far will a block weighing 18 N stretch it?

Answer 1

Given

Spring constant, k=56 N/m

The weight of the block, F=18 N

To find

The stretch in the spring

Step-by-step explanation

By hook's law,

`F=kx`

where x is amount the spring is stretched.

Putting the values,

`\begin{gathered} 18=56x \\ \Rightarrow x=0.32 \end{gathered}`

Conclusion

The amount by which the spring is stretched is 0.32 m