Question

In Triangle NOP, n = 7.4 cm, o = 8.7 cm and Angle P=61°. Find the area of Triangle NOP, to the nearest10th of a square centimeter.

Answer 1

We have that the area of a triangle using two sides and the angle between those sides can be determined using the following expression:

`A=ab(\sin (\theta))/(2)`

Now, we replace and operate:

`A=(7.4)(8.7)(\sin(61))/(2)\Rightarrow A\approx28.2`

So, the area of the triangle is approximately 28.2 squared centimeters.