Question

What is the value of this expression: if h = 8, j = -1, and k = -12? a.) 12b.) 36c.) -12d.) 3/2

Answer 1

Given the expression:

`\frac{j^3k^{}}{h^0}`

Where,

h = 8

j = -1

k = -12

Let's plug in the values to the expression:

`\frac{j^3k^{}}{h^0}`
`\frac{(-1)^3(-12)^{}}{8^0}`

Recall: Any number that is raised to the power of zero is always equal to 1.

We get,

`\frac{(-1)^3(-12)^{}}{8^0}\text{ = }((-1)(-12))/(1)\text{ = (-1)(-12)}`

Recall: When multiplying integers of the same sign, the product is always a positive integer.

We get,

`(-1)(-12)\text{ = 12}`

Therefore, the answer is 12, letter A.