Question

2 Given f(x) = 45x" - 41x + 4 and g(x) = 9x - 1, where g(x) = 0, find (x). .

Answer 1

As given functions are:

`\begin{gathered} f(x)=45x^2-41x+4 \\ g(x)=9x-1 \end{gathered}`

Given that g(x)=0, So:

`\begin{gathered} g(x)=0 \\ 9x-1=0 \\ x=(1)/(9) \end{gathered}`

Now put the value of x in f(x):

`\begin{gathered} f(x)=45((1)/(9))^2-41((1)/(9))+4 \\ f(x)=45((1)/(81))-(41)/(9)+4 \\ f(x)=(5)/(9)+4-(41)/(9) \\ f(x)=(5+36-41)/(9) \\ f(x)=(41-41)/(9) \\ f(x)=0 \end{gathered}`

So the value of f(x) is 0.