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What is the vertex of: y=x^2+10x+26
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What is the vertex of: y=x^2+10x+26
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Apr 18, 2022
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What is the vertex of:
y=x^2+10x+26
Mathematics
college
Ofundefined
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Answer:
the vertex is (-5,1)
Explanation:
hoped I helped:)
Splrs
answered
Apr 22, 2022
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Splrs
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