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The sum of Sally and Beth's age is 60. Six years ago, Sally was 3 times as old as Beth. What are their present ages?

1 Answer

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6 years ago, the sum of their ages would be 12 less than it is now.
60 - 12 = 48.
Now, if one was three times as old as the other, then we need to find 4 equal parts. 48 divided by 4 is 12. So, 6 years ago, Beth was 12 and Sally was 36.
So, now we put the 6 years back on to each, and get:

Sally is 42 and Beth is 18.

That is the easiest way i can see, but there might be a better way to do it.
User Akhil Dabral
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