Question

A pendulum has a mass of 1.5 kg and starts at a height of 0.4 m. If it is released from rest, how fast is it going when it reaches the lowest point of its path? Acceleration due to gravity is g = 9.8 m/s2.

Answer 1

Assuming the lowest point of its path is at a height of 0 m, I would use the concept of conservation of energy:

At the highest point, the pendulum has no kinetic energy since its velocity is zero, so the total energy at that point is:

`E = mgh`
At the lowest point the potential energy is zero since the height h = 0, and now the energy reads:

`E = (1)/(2) m v^(2)`

Since no energy is lost:

`mgh = (1)/(2) m v^(2)`

Solve for v:

`v = √(2gh)`

Answer 2

Answer:it's 2.8m/s

Explanation: sir Coochie man said so