Question

Please select the best answer from the choices provided

Answer 1

When using the given quadratic regression equation, the predicted y-value is approximately 555.5 when the x-value is 200, corresponding to option D.

To predict the y-value when the x-value is 200 using the quadratic regression equation y = 0.008x^2 + 0.518x + 131.886, we substitute x with 200:

y = 0.008(200)^2 + 0.518(200) + 131.886

y = 0.008(40000) + 103.6 + 131.886

y = 320 + 103.6 + 131.886

y = 555.486

Thus, the predicted y-value is approximately 555.5 when the x-value is 200, which corresponds to answer option D.

The probable question may be:

Make a scatter plot of data below

x 25,50,75,100,125,150,175

y 150,178,216,265,323,392,470.4

Using quadratic regression equation

y=0.008x^2+0.518x+131.886

predict what is the y-value will be if x-value is 200

A. y=83.5

B. y=346.9

C. y=238.1

D. y=555.5

Answer 2

D. y= 555.5

Explanation:

We are given,

The quadratic regression equation is
`y=0.008x^2+0.518x+131.886`

It is required to predict the y-value, when the x-value is 200.

Substituting x= 200, we get,

`y=0.008x^2+0.518x+131.886\\\\y=0.008* 200^2+0.518* 200+131.886\\\\y=0.008* 40000+0.518* 200+131.886\\\\y=320+103.6+131.886\\\\y=555.5`

Thus, the predicted y-value is 555.5 when x= 200.

So, option D is correct.