Question

When 8 moles of lithium metal react with excess oxygen gas, how many moles of lithium oxide can be produced? 4Li + O2 → 2Li2O

a. 2
b. 4
c. 8
d. 16

Answer 1

4li + o2 ----> 2li2o
8 x

cross multiply 8x2 ÷ 4x
x=4

the answer is 4

Answer 2

Answer: Option (b) is the correct answer.

Step-by-step explanation:

The given reaction is as follows.

`4Li + O_(2) \rightarrow 2Li_(2)O`

Also, it is given that 8 moles of lithium metal on reaction with excess of oxygen results in the formation of lithium oxide.

Let the number of moles of lithium oxide is x. 4 lithium atoms give 2 atoms of lithium oxide, therefore, divide the number of moles of lithium by half as follows.

Number of moles of lithium = number of moles of lithium oxide

8 = 2x

or, x =
`(8)/(2)`

x = 4

Thus, we can conclude that when 8 moles of lithium metal react with excess oxygen gas, then 4 moles of lithium oxide can be produced.