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Given that ka for hclo is 4.0 x 10-8 at 25 °c, what is the value of kb for clo- at 25 c
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Given that ka for hclo is 4.0 x 10-8 at 25 °c, what is the value of kb for clo- at 25 c

User Merna Mustafa
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The Ka of HClO is 4.0 x 10^-8 at 25 C. The dissociation of HClO is:

HClO + H2O ---> H+ + ClO - T = 25 C

Ka = 4.0 x 10^-8 = [H+][ClO-]/[HClO]

pH = -log[4.0 x 10^-8]
pH = 7.40
pOH = 14 - 7.40
= 6.60
Kb = 10^-6.6

User Matthew Perron
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