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What is the impulse of a baseball thrown with a force of 75 N when in contact with the pitcher's

hand for 0.050 seconds?

1 Answer

6 votes

Answer:

3.75Ns

Step-by-step explanation:

Given data

F= 75N

time= 0.05seconds

We know that

P=Ft

substitute

P=75*0.05

P=3.75Ns

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