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What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

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5 votes
Use the quadratic formula
a = 2 b = 16 c = -9

x = [-b +-sq root (b^2 - 4*a*c)] / 2*a
x = [-16 +- sq root (256 -4*-18)] / 4
x = [-16 +- sq root (256 +72)] / 4
x = (-16 +- 18.11) / 4
x1 = .5275

x2 = -8.5275


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