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9 votes
What is the magnitude of the centripetal

force that must be applied in order for a

0.5 kg ball on a 2.0 m string to spin with

uniform circular motion at 5.0 m/s?

User Nahoang
by
6.3k points

2 Answers

9 votes

Final answer:

The magnitude of the centripetal force required for a 0.5 kg ball to spin in uniform circular motion at 5.0 m/s on a 2.0 m string is 6.25 Newtons.

Step-by-step explanation:

To find the magnitude of the centripetal force, we can use the formula F = m × ac, where m is the mass of the object, and ac is the centripetal acceleration. Centripetal acceleration is given by the formula ac = v² / r, where v is the linear speed and r is the radius of the circular path.

Given the mass m = 0.5 kg, the speed v = 5.0 m/s, and the string length (radius) r = 2.0 m, we can calculate the centripetal acceleration as:

ac = v² / r = (5.0 m/s)² / 2.0 m = 25 m²/s² / 2.0 m = 12.5 m/s²

Now we can compute the centripetal force:

F = m × ac = 0.5 kg × 12.5 m/s² = 6.25 N

Thus, the centripetal force required is 6.25 Newtons.

User Bmons
by
4.8k points
1 vote

Answer:

Step-by-step explanation:

6.25

What is the magnitude of the centripetal force that must be applied in order for a-example-1
User Lenny
by
6.5k points