Question

Graph the system below2x-3y=-183x+y=-5

Answer 1

Explanation:

We have the following system of equations:

`\begin{gathered} 2x-3y=-18 \\ \\ 3x+y=-5 \end{gathered}`

To graph, we calculate the intercepts in each equation to then draw the straight line corresponding to each equation, like this:

`\begin{gathered} \text{ For }2x-3y=-18 \\ \\ \text{The x-intercept} \\ \\ \:2x-3\cdot 0=-18 \\ \\ x=-9\rightarrow(-9,0) \\ \\ \text{The y -intercept} \\ \\ 2\cdot0-3y=-18 \\ \\ y=6\rightarrow(0,6) \\ \\ \\ \text{For }3x+y=-5 \\ \\ \text{The x-intercept} \\ \\ 3x+0=-5 \\ \\ x=-(5)/(3)\rightarrow\left(-(3)/(5),0\right) \\ \\ \text{The y- intercept} \\ \\ \:3\cdot 0+y=-5\: \\ \\ y=-5\rightarrow(0,-5) \end{gathered}`

Now we graph: