Question

A series circuit consists of a 100-ω resistor, a 10.0-μf capacitor, and a 0.350-h inductor. the circuit is connected to a 120-v rms, 60-hz power supply. what is the rms current in the circuit?

Answer 1

current will be
`I=(V_(rms))/(Z)=\frac{V_(rms)}{\sqrt{ R^(2)+(X_(C)-X_(L))^(2)}}\\where~X_(c)=(1)/(j.\omega .C)~and~X_(L)=j.\omega.L~where~\omega=2.\pi f~and~f=60Hz`
now just pluf in the values and Voila..