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4 votes
Which of the following is the correct factorization of the polynomial below?

64x3 + 27

A. (16x + 8)(3x2 - 12x + 9)
B. (4x + 3)(16x2 - 12x + 9)
C. (3x2 + 4)(3x - 16x + 16)
D. The polynomial is irreducible.

User ZoolWay
by
6.5k points

2 Answers

5 votes
64x^3 + 27 is a sum of cubes: (4x)^3 + 3^3, for which the factors are (4x + 3)(16x^2 - 12x + 9)
User Daerin
by
6.0k points
2 votes

Answer: the correct option is

(B)
(4x+3)(16x^2-12x+9).

Step-by-step explanation: We are given to select the correct factorization of the following polynomial :


P=64x^3+27.

We will be using the following factorization formula :


a^3+b^3=(a+b)(a^2-ab+b^2).

Therefore, the factorization of the given polynomial is as follows :


P\\\\=64x^3+27\\\\=(4x)^3+3^3\\\\=(4x+3)((4x)^2-4x*3+3^2)\\\\=(4x+3)(16x^2-12x+9).

Thus, the required factored form is
(4x+3)(16x^2-12x+9).

Option (B) is CORRECT.

User Jirinovo
by
6.4k points