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Select the conic section that represents the equation.3x² + 3y²-2x + 4 = 0

User Calon
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1 Answer

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22 votes

Given:


3x^2+3y^2-2x+4=0

First, we arrange the equation:


\begin{gathered} 3x^(2)+3y^(2)-2x+4=0 \\ 3x^2-2x+3y^2+4=0 \\ (3x^2-2x)+3y^2=-4 \end{gathered}

Further simplification of the given equation will give us a result with an imaginary number, making the equation a nonreal circle, or not a conic section.

User Azher Aleem
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