Question

A spinner with six sections labeled A through F is spun. The probability of spinning a consonant (B, C, D, or F) is 23 . What is the probability of not spinning a consonant? Enter your answer as a fraction, in simplest form, in the box.

Answer 1

`1-(2)/(3)=(1)/(3)`

It's 1/3.

Answer 2

Answer:
`(1)/(3)`

Explanation:

Given: A spinner with six sections labeled A through F is spun.

The probability of spinning a consonant (B, C, D, or F) =
`(2)/(3)`

Then, the probability of not spinning a consonant

= 1 - probability of spinning a consonant

Thus, the probability of not spinning a consonant =
`1-(2)/(3)`

Hence, the probability of not spinning a consonant =
`(1)/(3)`