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A 12- sided number cube with the numbers 1 through 12 is rolled.

Rounded to the nearest humdreth, the probability that the number cube lands on a number greater than 10 is

User Jasdeep
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4 votes
I think it would be 2/12=1/6 or 0.17
User Alexisvt
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Answer:

Probability is 0.17.

Explanation:

Given : A 12- sided number cube with the numbers 1 through 12 is rolled.

To find : The probability that the number cube lands on a number greater than 10 ?

Solution :


\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}

A 12- sided number cube with the numbers 1 through 12 is rolled.

Total number of outcomes = 12

Number cube lands on a number greater than 10

Favorable outcomes(11 and 12)=2


\text{P(no. greater than 10)}=(2)/(12)


\text{P(no. greater than 10)}=(1)/(6)


\text{P(no. greater than 10)}=0.1666

Nearest to hundredth, Probability is 0.17.

User Daniel Nadasi
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