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What volume (in L) of nitrogen monoxide will be

required to produce 54.5 L of carbon dioxide in

the reaction below?

2CO(g) + 2NO(g) → N2(g) + 2CO2(g)

User Tam
by
3.5k points

2 Answers

8 votes

Answer:

54.5

Step-by-step explanation:

User Johnsonium
by
3.2k points
6 votes

Answer:

54.5 L of nitrogen monoxide, NO.

Step-by-step explanation:

The balanced equation for the reaction is given below:

2CO + 2NO —> N₂ + 2CO₂

From the balanced equation above,

2 L of NO reacted to produce 2 L of CO₂.

Finally, we shall determine the volume of nitrogen monoxide, NO, required to produce 54.5 L of carbon dioxide, CO₂. This can be obtained as follow:

From the balanced equation above,

2 L of NO reacted to produce 2 L of CO₂.

Therefore, 54.5 L of NO will also react to produce 54.5 L of CO₂.

Thus, 54.5 L of nitrogen monoxide, NO, is needed for the reaction.

User DisturbedNeo
by
3.5k points