Question

What volume will 0.75 moles of oxygen gas occupy at STP?

Answer 1

I believe the answer would be 16.8

Answer 2

Answer: Volume occupied by oxygen gas at STP is 16.78 liters.

Step-by-step explanation:

At STP, value of pressure ,P = 1atm

At STP, value of Temperature ,T = 273 K

Number moles of oxygen gas ,n= 0.75 moles

According to ideal gas equation :

PV=nRT, R = Universal Gas constant = 0.0820 L atm/mol K

`1 atm* V=0.75 mol* 0.0820 L atm/mol K* 273 K`

`V=(0.75 mol* 0.0820 L atm/mol K* 273 K)/(1 atm)=16.78 L`

Volume occupied by oxygen gas at STP is 16.78 liters.