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37 votes
In the accompanying diagram of BCD m

In the accompanying diagram of BCD m-example-1
User Rjc
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1 Answer

24 votes
24 votes

Given:

m∠C = 70°

m∠CDE = 130°

Question 1:

To find ∠CDB, let's use the exterior angle theorem.

The exterior angle theorem states that the sum of 2 opposite interior angles is equal to the exterior angle.

Thus,

m∠C + m∠B = 130

70 + m∠B = 130

Subtract 70 from both sides:

70 - 70 + m∠B = 130 -70

m∠B = 60°

Now, use the triangle angle sum theorem to find ∠CDB.

The triangle angle sum theorem states that the sum of interior angles in a triangle is 180°

∠CDB = 180 - 70 - 60 = 50°

∠CDB = 50°

Question 2:

∠CBA = ∠C + ∠CDB

∠CBA = 70 + 50 = 120°

∠CBA = 120°

ANSWER:

∠CDB = 50°

∠CBA = 120°

User Xcecution
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