Question

PLEASE HELP ME! ITS DUE TODAY!!!!

:Find all values of x such that $2x^2 +9x - 5=0$ . If you find more than one value, then list your solutions in increasing order, separated by commas.

Answer 1

X = -5, X = 1/2 Hope this helped!

Answer 2

x = -5,
`(1)/(2)`

Explanation:

The given equation is 2x² + 9x - 5 = 0

We have to find the values of x.

We know that if in a quadratic equation ax²+ bx + c = 0, b²- 4ac > 0 then there will be two real roots of the equation.

In the given equation b²- 4ac = (9)²-4(2)(-5) = 81 + 40

= 212 > 0

So there will be two real roots.

Now we will factorize the given equation.

2x² + 9x - 5 = 0

2x² + 10x - x - 5 = 0

2x(x + 5) - 1(x + 5) = 0

(2x - 1)(x + 5) = 0

So two roots will be 2x - 1 = 0

x =
`(1)/(2)`

and x + 5 = 0

x = -5

Therefore, x = -5,
`(1)/(2)` are the solutions.