Question

5.

A badminton shuttlecock leaves the racquet traveling 30 m/s. It goes over the net 0.5
seconds later with a speed of 10 m/s. Calculate its average acceleration.

Answer 1

`a=40\ m/s^2`

Step-by-step explanation:

Given that,

Initial speed of a shuttlecock, u = 30 m/s

Final speed of the shuttlecock, v = 10 m/s

Time, t = 0.5 s

We need to find its average acceleration. The acceleration of an object is equal to the change in speed divided by time taken. It is given by :

`a=(v-u)/(t)\\\\a=(10-30)/(0.5)\\\\a=-40\ m/s^2`

So, the average acceleration of badminton shuttlecock is
`40\ m/s^2`.