Question

If the evaluate of a is negative and the vertex is at (13, -2) then how many x-interceps will the graph?

A) 2
B) It cannot be determined from the information
C)0
D) 1

Answer 1

y=a(x-h)²+k
vertex is (h,k)
and when a is positive then the parabola opens up and the vertex is lowest point

so since vertex is (13,-2) then it is below the x axis (-2<0)
and since a is negative, it opens down
so the vertex is the highest point
since the highest point is already below the x axis, there cannot be any x intercepts



0 intercepts
answer is C

Answer 2

ugh i believe the answer would be A