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2 votes
4000

Amount
saved ($)
2000
o
6
2. 4
Months in plan
The graph shows the activity in a savings account.
a. What was the amount of the initial deposit that started this savings account (don't use commas)?$
b. Find the slope.
c. Find the y-intercept.
d. Write an equation in slope-interce
form for the activity in this savings account.

4000 Amount saved ($) 2000 o 6 2. 4 Months in plan The graph shows the activity in-example-1

1 Answer

10 votes

Answer:

$1000 ; 500 ; 1000 ; y = 500x + 1000

Explanation:

From the graph, the initial deposit which started the savings account is $1000 ; this is the value on the y - intercept, the value in the account at time or period = 0.

The slope :

x1 = 0 ; y1 = 1000

x2 = 6 ; y2 = 4000

Slope = Rise / Run

Rise = y2 - y1 = 4000 - 1000 = 3000

Run = x2 - x1 = 6 - 0 = 6

Hence,

Slope = 3000 / 6

Slope = 500

y - intercept = 1000 (from. Graph)

Equation in slope intercept form:

General form : y = mx + c

m = slope ; c = intercept

Equation is written as ;

y = 500x + 1000

User Valamburi M
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