Question

A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s2. What is the final velocity of the train?

Answer 1

`7.5m/s`

Step-by-step explanation:

We use the formula to find the final velocity for the movement with constant acceleration:

`V_(f)=V_(i)+at`

where

`V_(f)` is the final velocity of the train

`V_(i)` is the initial velocity of the train, since it starts from rest
`V_(i)=0`

`a` is the acceleration,
`a=1.5m/s^2`

and
`t` is the interval of time,
`t=5s`

So, replacing the values in the formula we get:

`V_(f)=0+(1.5m/s^2)(5s)`

`V_(f)=7.5m/s`

The final velocity of the train is
`7.5m/s`

Answer 2

Final speed of the train is 7.5 m/s

Step-by-step explanation:

It is given that,

Uniform acceleration of the train is, a = 1.5 m/s²

It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :

`v=u+at`

Here, train starts from rest so, u = 0

`v=0+1.5\ m/s^2* 5\ s`

v = 7.5 m/s

So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.